知识集|运筹学系统可靠性问题(运筹学会可靠性分会)

知识集|运筹学系统可靠性问题(运筹学会可靠性分会)

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今天小编为大家带来管理原理知识分享(七):人群关系理论(梅奥的华桑实验),欢迎您的访问。

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Dear youundefined this is The LearningYard Academy.

Today Xiaobian brings you the knowledge sharing of management principles (7): Crowd Relationship Theory (Mayo's Huasang experiment)undefined welcome to your visit.

今天是系统可靠性的例题

Today is an example of system reliability

某科研项目组由三个小组用不同的手段分别研究,它们失败的概率各为0.40,0.60,0.80。为了减少三个小组都失败的可能性,现决定给三个小组中增派两名高级科学家,到各小组后,各小组科研项目失败概率如下表,问如何分派科学家才能使三个小组都失败的概率(即科研项目最终失败的概率)最小?

知识集|运筹学系统可靠性问题(运筹学会可靠性分会)

A scientific research project team is studied separately by three groups with different means, and the probability of failure is 0.40, 0.60, and 0.80 respectively. In order to reduce the likelihood that all three groups will fail, it has been decided to send two additional senior scientists to the three groups, and after each group, the probability of failure of the scientific research projects of each group is as follows,How do scientists be assigned to minimize the probability that all three groups will fail (i.e., the probability that a scientific project will eventually fail)?

首先对K、sk、xk进行参数说明

First, the parameters of K, sk, and xk are described

然后是第三阶段,此阶段可用科学家数以及可取科学家数范围都在0到2万元,而考虑最大效益只需考虑此阶段,故x3的取值即为可取的工作日数,即对角线。计算如下.

Then there is the third stage, the number of available scientists and the number of desirable scientists in this stage range from 0 to 20,000 yuan, and the maximum benefit only needs to consider this stage, so the value of x3 is the desirable number of working days, that is, the diagonal. The calculation is as follows.

知识集|运筹学系统可靠性问题(运筹学会可靠性分会)

接下来是第二阶段,此阶段可用科学家数以及可取科学家数范围也都在0到2万元,此阶段需考虑第三阶段的概率。例如,当sk为1,第二阶段取1时,综合概率便为第二组1个专家的0.4与第一阶段0个专家0.8的乘积0.32,具体计算如下.

Next is the second stage, the number of available scientists and the number of desirable scientists in this stage also range from 0 to 20,000 yuan, this stage needs to consider the probability of the third stage. For example, when the sk is 1 and the second stage takes 1, the comprehensive probability is the product of 0.4 of the second group of 1 expert and 0.8 of the 0.8 of the 0 experts in the first stage, which is calculated as follows.

知识集|运筹学系统可靠性问题(运筹学会可靠性分会)

最后是第一阶段,与后两阶段不同的是,可用科学家数为4万元,可取科学家数的范围在0到2万元,计算过程如下.

Finally, the first stage, unlike the last two stages, the number of available scientists is 40,000 yuan, and the desirable number of scientists ranges from 0 to 20,000 yuan, and the calculation process is as follows.

知识集|运筹学系统可靠性问题(运筹学会可靠性分会)

今天的分享就到这里了。如果您对今天的文章有什么独特的想法,欢迎评论留言,让我们相约明天,祝您今天过得开心快乐!

That's it for today's sharing. If you have any unique ideas for today's articleundefined please leave a commentundefined let us meet tomorrowundefined I wish you a happy day!

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